Solving equations with exponents quizlet

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Consider these two equations:

Equation 1: x2 = four and Equation 2: x3 = 27

Equation 1 has two solutions: 2 and -2 considering the fact that 22 = 4 and (-2)2 = four.

Equation 2 only has one answer: x = 3.

Whenever an equation carries all even exponents, you need to recall each the choices tremendous and terrible solutions. If the choices exponent is an ordinary power, there’s simplest one answer.

Solving Equations with Exponents: xm=okay

If m is even: x = ±m√ okay

If m is ordinary: x = m√ okay

For equations which encompass roots apart from the square root, you want to do away with the roots by means of (1) isolating the choices root time period on one aspect of the choices equation, and (2) raising each facets of the equation to the appropriate strength.

Example 1. Solve (x² + 6x)1/four = 2

Recall that a fractional exponent is certainly a root: am/n = (n√ a ) m

Remove the 4th root with the aid of elevating every side of the choices equation to the choices 4th energy.

Simplify each aspect of the choices equation.

Set the choices equation equal to 0.

Factor the choices left aspect of the choices equation.

Set factors equal to 0 and remedy.

Our viable answers are x = − eight and x = 2. Both of these answers want to be checked the use of the original equation.

2 = 2 is a real assertion. Therefore x = − 8 is a solution.

2 = 2 is a real assertion. Therefore x = 2 is an answer.

The answers to the choices equation,(x² + 6x)1/4 = 2, are x = − eight and x = 2.

Example 2 : Solve for w: 5w2/3 + three = 23

Isolate the choices w-time period on the choices left side of the equation. Subtract three from each aspect of the choices equation.

Divide each side of the equation through five.

Isolate the w by way of raising both facets of the equation to the choices three/2 electricity. Since the numerator of the exponent is even, there can be answers.

The two answers to the equation, 5w2/three + three = 23, are 8 and -8.

Raise both facets of the equation to the reciprocal of the choices exponent.

The correct reaction: b

Raise each aspects of the choices equation to the choices reciprocal of the exponent.

The correct response: c

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